Answer:
OPTION B: {5, 7, 9}
Step-by-step explanation:
D [tex]$ \cap $[/tex] E is the collection of elements that are present in both D and E.
Given the set D = {5, 6, 7, 8, 9, 10}
and E = {1, 3, 5, 7, 9, 11}
So, the elements present in both D and E are: {5, 7, 9}.
Hence, D [tex]$ \cap $[/tex] E = {5, 7, 9}.
OPTION B is the answer.
