Empirical formula of the compound contains 5 carbon atoms.
Explanation:
We have the molecular formula of the compound C₁₀H₂₂O₂.
To find the empirical formula we divide each number of atoms by the lowest number which is 2:
for carbon (C) 10 / 2 = 5
for hydrogen (H) 22 / 2 = 11
for oxygen (O) 2 / 2 = 1
The empirical formula is C₅H₁₁O and contains 5 carbon atoms.
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