If 3x-y=12, what is the value of 8x/2y?
Answer:
[tex]\frac{8x}{2y} =\frac{4x}{3x-12}[/tex]
Step-by-step explanation:
[tex]3x-y=12[/tex]
[tex]-y=12-3x[/tex]
[tex]y=3x-12[/tex]-------------------------(equation 1)
Now,
[tex]\frac{8x}{2y} =\frac{8x}{2(3x-12)}[/tex]---------(from equation 1)
[tex]=\frac{8x}{6x-24}[/tex]
[tex]=\frac{8x}{2(3x-12)}[/tex]
[tex]=\frac{4x}{3x-12}[/tex]
Therefore, the value of [tex]\frac{8x}{2y} =\frac{4x}{3x-12}[/tex]
