For this case we have that by definition, the equation of a line of the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut-off point with the y axis
According to the statement data we have:
[tex]m = 3[/tex]
Thus, the line is of the form:
[tex]y = 3x + b[/tex]
We substitute point [tex](-1,6)[/tex] and find "b":
[tex]6 = 3 (-1) + b\\6 = -3 + b\\6 + 3 = b\\b = 9[/tex]
Finally, the equation is:
[tex]y = 3x + 9[/tex]
Answer:
[tex]y = 3x + 9[/tex]
