katiemickey9
katiemickey9 katiemickey9
  • 16-11-2019
  • Mathematics
contestada

Check all of the functions that are odd.
f (x)=x^3-x^2
f(x)=x^5-3x^3+2x
f(x) = 4x + 9
F(x)=1/x

Respuesta :

yasminelena
yasminelena yasminelena
  • 17-11-2019

Answer:

f(x)= 4x+9

F(x)=1/x

Step-by-step explanation:

An odd function accomplish the following condition:

f(-x) = -f(x) (1)

By checking (1) on each of the next functions, we have:

f(-x) = (-x)^3 - (-x)^2  [tex]\neq[/tex] -f(x) = - (x^3- x^2)

f(-x) = (-x)^5 -3(-x)^3 + 2(-x) [tex]\neq[/tex] -f(x) = -x^5 +3x^3 +2x

f(-x)= -4x +9 = -f(x)

F(-x) = -1/x =-F(x)

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