Respuesta :

ebanzz
53.3 %
glucose, so the mass of oxygen in 1 mole of glucose = 6 × 16.00 g = 96.00 g. % oxygen = 96.00 × 100 % = 53.3 % by mass. 180.18 [Note that the sum of the % of all the elements must add up to 100 %.]

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