Answer:
The current is 0.248 A
Explanation:
Given that,
Inductor [tex]L= 45\times10^{3}\ H[/tex]
Resistance [tex]R= 60\Omega[/tex]
Voltage = 15 volt
Time [tex]t =7.0\times10^{-3}\ sec[/tex]
We need to calculate the current
Using formula of current
[tex]I=\dfrac{V}{R}(1-e^{\dfrac{-R}{L}}t)[/tex]
Where, V = voltage
R = resistance
L = inductance
T = time
Put the value into the formula
[tex]I=\dfrac{15}{60}(1-e^{\dfrac{-60}{45\times10^{3}}}\times7\times10^{-3})[/tex]
[tex]I=0.248\ A[/tex]
Hence, The current is 0.248 A.
