Answer:
for f(x) = 4x², x≥0, the inverse function is f⁻¹(x) = (1/2)√x
Step-by-step explanation:
Solve for y:
x = f(y) = 4y^2
(x/4) = y^2
±√(x/4) = y = ±(1/2)√x
The domain of the original function must be restricted if it is to have an inverse. (The inverse relation cannot be double-valued if it is to be called an inverse function.) Usually we choose to restrict the values of x to be positive.
for f(x) = 4x², x≥0, the inverse function is f⁻¹(x) = (1/2)√x
