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A particle of mas 0.1 kg moves along the trajectory x(t)-3t t where x is in meters and t is in seconds. What is the kinetic energy of the particle at time t? Select one: a. 0.3 (t 1)3 o b. 0.25 (t2 -1) c. 0.25 (t + 1)2 d. 0.45 (t2+1)2 o e. 3.0 (1-)

Respuesta :

Answer:

Kinetic energy = 0.45 joules

Explanation:

We have velocity of the particle is

[tex]v=\frac{dx(t)}{dt}\\\\v=\frac{d(3t)}{dt}\\v=3m/s[/tex]

Now kinetic energy(K.E) is given by

[tex]K.E=\frac{1}{2}mv^{2}[/tex]

applying values we get

Kinetic energy =[tex]\frac{1}{2}0.1\times 3^{2}\\\\\therefore K.E=0.45Joules[/tex]

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