angel8155 angel8155
  • 17-06-2019
  • Mathematics
contestada

i know it’s not a ser choice a but im still not sure

i know its not a ser choice a but im still not sure class=

Respuesta :

gmany
gmany gmany
  • 23-06-2019

Step-by-step explanation:

[tex]f(x)=\dfrac{2}{x}\ and\ g(x)=\dfrac{2}{x}\\\\(f\circ g)(x)=f(g(x))\to\text{substitute}\ 2-3x\ \text{instead}\ x\ \text{in}\ f(x):\\\\(f\circ g)(x)=\dfrac{2}{\frac{2}{x}}=2\cdot\dfrac{x}{2}=x[/tex]

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