For this case we have by definition, that the volume of a sphere is given by:
[tex]V = \frac {4} {3} \pi * r ^ 3[/tex]
Where:
r: It is the radius of the sphere
If the radius is divided by 3 we have:
[tex]\frac {r} {3}:[/tex]
[tex]V = \frac {4} {3} \pi * (\frac {r} {3}) ^ 3\\V = \frac {4} {3} \pi * \frac {r ^ 3} {27}\\V = \frac {4} {81} \pi * r ^ 3[/tex]
ANswer:
the volume decreases considerably because the denominator increases
