jasminelockhart7983 jasminelockhart7983
  • 18-04-2019
  • Mathematics
contestada

Suppose you have a right triangle with congruent legs and a hypotenuse that measure 26 square-root of 2 divided by 5. What is the length of one of the legs? Round to the nearest tenth.

Respuesta :

calculista
calculista calculista
  • 28-04-2019

Answer:

[tex]5.2\ units[/tex]

Step-by-step explanation:

Let

x-----> the length of the congruent legs

we know that

If the triangle is a right triangle with congruent legs

then

the measures of the internal angles are 45°-90°-45°

therefore

[tex]cos(45\°)=\frac{x}{(26\sqrt{2}/5)}[/tex]

[tex]cos(45\°)=\frac{\sqrt{2}}{2}[/tex]

so

[tex]\frac{\sqrt{2}}{2}=\frac{x}{(26\sqrt{2}/5)}\\ \\x=26/5\\ \\x=5.2\ units[/tex]

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