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22-02-2019
Mathematics

contestada

Solve.
2x + 12 ≥ 6

x ≥ - 3
x ≤ 3
x ≤ - 3
x ≥ 3

Respuesta :

22-02-2019

x _>_ -3

[tex]2x + 12 \geqslant 6 = 2x \geqslant - 6 = x \geqslant - 3 [/tex]

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