alfonxinecaoowt3te alfonxinecaoowt3te
  • 21-02-2019
  • Mathematics
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Kim ((sqrt t^2 -9)-3)/t^2 as t tends to 0 on both sides​

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LammettHash
LammettHash LammettHash
  • 21-02-2019

The limit doesn't exist. Notice that [tex]\sqrt{t^2-9}[/tex] is defined only for [tex]t^2\ge9[/tex], or [tex]|t|\ge3[/tex], or [tex]t\le-3[/tex] and [tex]t\ge3[/tex]. In other words, [tex]\dfrac{\sqrt{t^2-9}-3}{t^2}[/tex] doesn't exist for any [tex]t[/tex] between -3 and 3.

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