Answer:
[tex]3a(14x+21y)(2b-1)[/tex]
Step-by-step explanation:
Given, [tex](14x+21y)(6ab-3a)[/tex]
[tex](14x+21y)(6ab-3a)=(14x+21y)(3\times2ab-3\times a)[/tex]
[tex]3[/tex] and [tex]a[/tex] are common factors in second factor
[tex](14x+21y)(6ab-3a)=3a(14x+21y)(2b-1)[/tex]
Hence, the product of two binomial is written in two binomial and a monomial.
