I think the answer to question b is to add 2 every time you want to get the next square.
Hope it helped! :)
Answer:
Step-by-step explanation:
sum of 1st nth odd numbers: 1+3+5+7+9+...+n
its an arithmetic series an=a1+(n-1)d where a1=1 n d=2
sum is given by n*(a1+an)/2
=n*(1+1+(n-1)*2)/2
=n*(2+2n-2)/2
=n*(2n)/2
=n^2
