According to table : [tex]a_1= -1.[/tex]
[tex]a_2= 1[/tex]
[tex]a_3= 3[/tex]
[tex]a_4=5[/tex].
Now, we can find common difference, : second term - first term = 1-(-1) = 1+1=2.
We know formula for a recursive sequance of an arithmetic sequence is
[tex]a_n=a_{n-1}+d[/tex], where n is the number of term and d is the common difference.
If we plug d=2 in that formula, we would get
[tex]a_n=a_{n-1}+2.[/tex]
Therefore, correct option is second [tex]a_n=a_{n-1}+2[/tex] option.
