Answer- Probability of getting all heads is 0.25
Solution-
As the outcome of the first experiment is know to be Heads. So the sample space becomes
S = {(H, H, H),(H, H, T),(H, T, H),(H, T , T)}
[tex]\left | S \right | = 4[/tex]
[tex]\left | E \right |= Getting \ all \ heads = 1[/tex]
[tex]P(E) = \frac{\left | E \right |}{\left | S \right |} = 0.25[/tex]
