paulfdavis1977 paulfdavis1977
  • 16-09-2018
  • Physics
contestada

A 3 mg bullet is fired from a 1 kg musket with a velocity of 3,000. m/s. What is the resulting velocity of the musket?

Respuesta :

aristocles aristocles
  • 26-09-2018

by momentum conservation we can say

[tex]P_i = P_f[/tex]

since gun and bullet was initially at rest so initial momentum of both must be ZERO

[tex]0 = m_1v_{1f} + m_2v_{2f}[/tex]

[tex]0 = 3* 10^{-3}* 3000 + 1 * v_{2f}[/tex]

[tex]0 = 9 + v_{2f}[/tex]

[tex]v_{2f} = - 9 m/s[/tex]

so it will recoil back with speed 9 m/s

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