Abbeecadaver Abbeecadaver
  • 17-03-2016
  • Mathematics
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solve 15>-3x or 2/5x>-2

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  • 17-03-2016
[tex]15\ \textgreater \ -3x \\ \\ - \frac{15}{3} \ \textless \ x \\ \\ -5 \ \textless \ x \\ \\ x \ \textgreater \ -5 \\ \\ [/tex]

The final result is: x > -5.

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[tex] \frac{2}{5} x \ \textgreater \ -2 \\ \\ \frac{2x}{5} \ \textgreater \ -2 \\ \\ 2x \ \textgreater \ -2 \times 5 \\ \\ 2x \ \textgreater \ -10 \\ \\ x \ \textgreater \ - \frac{10}{2} \\ \\ x \ \textgreater \ -5 \\ \\ [/tex]

The final result is: x > -5.
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