chris123645 chris123645
  • 17-06-2018
  • Chemistry
contestada

What volume of 0.330 M Na2co3 (106g/mol) solution contains 32.7 of Na2co3?

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dexteright02
dexteright02 dexteright02
  • 17-06-2018
Hello!

We having the following data:

V (volume) = ? (in L)
M (molar concentration) = 0.330 M (Mol/L)
MM (Molar Mass of Na2CO3) = 106 g/mol
m (mass of the solute) = 32.7 g

We apply the data to the molar formula or molar concentration, see:

[tex]M = \dfrac{m}{MM*V} [/tex]

[tex]0.330 = \dfrac{32.7}{106*V}[/tex]

[tex]0.330*106*V = 32.7[/tex]

[tex]34.98V = 32.7[/tex]

[tex]V = \dfrac{32.7}{34.98} [/tex]

[tex]\boxed{\boxed{V \approx 0.93\:L}}\end{array}}\qquad\checkmark[/tex]

I Hope this helps, greetings ... DexteR!
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