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a rock has a density of 15 g/cm3 and a mass of 50 g is dropped into a 100ml graduated cylinder containing 55 ml of water. to what height will the water rise in the cylinder

Respuesta :

Dejanras
Answer is: the height of cylinder is 58.33 ml.
d(rock) = 15 g/cm³.
m(rock) = 50 g.
V(rock) = m(rock) ÷ d(rock).
V(rock) = 50 g ÷ 15 g/cm³.
V(rock) = 3.33 cm³ = 3.33 ml..
h(cylinder) = V(rock) + V(water).
h(cylinder) = 3.33 cm³ + 55 cm³.
h(cylinder) = 58.33 cm³.
PBCHEM
We know that, Density = Mass/Volume


Therefore, Volume = Mass /Density = 50/15 = 3.33 ml

Thus, volume occupied by rock = 3.33 ml
 
Thus, total volume occupied in graduated cylinder = 55 ml + 3.33 = 58.33 ml 

∴volume of graduated cylinder will rise by 3.33 cm3.

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