Respuesta :

jakke1
Let the smallest integer be x
x + (x+2) + (x+4) + (x+6) = 288
4x +12 =288
4x= 276
x = 69
The integers are 69, 71, 73 and 75
fichoh

The set of consecutive odd integers which adds up to 288 are ; 69, 71, 73 and 75 respectively.

Let the consecutive odd integers be :

  • a, a+2, a+4, a+6

The sum can be expressed thus :

a + a + 2 + a + 4 + a + 6 = 288

4a + 12 = 288

4a = 288 - 12

4a = 276

a = 276 / 4

a = 69

Therefore, the consecutive odd integers are : 69, 71, 73, 75

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