1- FM is 3
we know that FM and FG are radius of the circle. so:
FM =FG
so if we find FG by Pythagorean theorem, we find FM, too
FL (hypotenuse) is 5
HL is 8. GL is half of HL. so GL is 4
now we can use Pythagorean theorem to find FG
[tex] 4 {}^{2} + {x}^{2} = {5}^{2} \\ {x}^{2} = {5}^{2} - {4}^{2} \\ {x}^{2} = 25 - 16 = 9 \\ x = \sqrt{9} = 3[/tex]
2- x is 40
BAD is half of m DB
ADB is half of m AB
so BAD is 50
and ADB is 90
Then ABD will be:
[tex]180 - (50 + 90) = 180 - 140 \\ = 40[/tex]
good luck
