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  • 16-05-2018
  • Mathematics
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What is the axis of symmetry of h(x)=5x^+40x+64

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gmany
gmany gmany
  • 16-05-2018
[tex]\text{The axis of symmetry of}\ f(x)=ax^2+bx+c\ is\ x=\dfrac{-b}{2a}.\\\\\text{We have:}\ h(x)=5x^2+40x+64\\\\\text{substitute:}\ x=\dfrac{-40}{2\cdot5}=\dfrac{-40}{10}=-4.\\\\Answer:\ \boxed{x=-4} [/tex]
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