Given the following equation and thermodynamic values answer the following. N2O(g) NO2(g) <--> 3 NO(g) At what temperature does this reaction change spontaneity. ΔH⁰ (N2O(g)) = 82.05 kJ ΔH⁰ (NO2(g) = 33.20 kJ ΔH⁰ (NO(g)) = 90.29 kJ ΔS⁰ (N2O(g)) = 219.7 J/mol ΔS⁰ (NO2(g) = 239.9 J/mol ΔS⁰ (NO(g)) = 210.65 J/mol