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19-03-2024
Chemistry

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Calculate the e.m.f of the following cell at 298 K: Fe(s) | Fe₂₊(0.001 M) || H⁺(0.01 M) | H2(g) (1 bar) | Pt(s)
Given that Ecell = 0.44= V [log 2 = 0.3010 log 3 = 0.4771 log 10 = 1]

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